Himalayan Ruellia is a herb 30-50 cm tall.
Stems rising up, 4-angled, brown
velvet-hairy. Leaf-stalks are 4-6 cm; leaf blade ovate to elliptic, 7.5-11
x 3.5-5 cm, papery, below velvet-hairy along veins, above hairy,
secondary veins about 6 on each side of midvein, base wedge-shaped to
narrowed and slightly oblique, margin entire, tip tapering. Flower-spikes are
borne at
branch-ends, 3-6 cm long. Bracts are round to kidney-shaped, about 1 x 1.4 cm,
gland-tipped velvet-hairy. Sepals are outside gland-tipped velvet-hairy;
posterior sepal ovate-elliptic, 8-10 mm, bractlike, other sepals linear to
subulate and 5-6 mm. Flowers are white, about 6 mm, lower lip 3-lobed, lobes
ovate-oblong and 1-2.4 × 0.6-1 mm; upper lip narrow, 2-lobed.
Capsule is ellipsoid, about 6 mm, tip gland-tipped velvet-hairy. Seeds
about 2 × 1.5 mm. Himalayan Ruellia is found
along forest margins, at altitudes of 400-900 m, in Easterm Himalayas,
Indo-China and W. China. Flowering: November-May.
Identification credit: Parjanya Guru, Tanay bose
Photographed in Sohra Forest, Cherapunjee, Meghalaya.
• Is this flower misidentified?
If yes,
Your name: Your email: Your comments
The flower labeled Himalayan Ruellia is ...